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AFOQT · Quantitative · AR and MK

AFOQT math: Arithmetic Reasoning and Math Knowledge

Updated Nov 6, 2026facts checked Nov 6, 2026

Two Form T subtests carry the math: Arithmetic Reasoning, 25 word problems, and Math Knowledge, 25 items of algebra and geometry. Together they make the Quantitative composite, and Math Knowledge on its own counts toward every rated composite.

AFOQT practice test AFOQT guide

How the AFOQT handles math

  • Fixed form: one item set for everyone and a separate clock for each subtest. Nothing adapts to your answers, unlike the computer-adaptive ASVAB.
  • Pace: about 70 seconds per Arithmetic Reasoning item and 53 per Math Knowledge item, worked out from AFPC's Table 2 limits. That is generous for a strong student and tight for anyone who sets up word problems slowly.
  • Paper only: AFPC's pamphlet does not mention a calculator; it says scratch paper is provided. Long division, fractions, percents and square roots have to be fast by hand.
  • Composites: both subtests feed Quantitative and Academic Aptitude. Math Knowledge also feeds Pilot, CSO and ABM; Arithmetic Reasoning left the Pilot composite when Form T replaced Form S.
  • Floor: the Quantitative minimum is the lowest commissioning floor on the test, yet AFPC's FAQ notes it has become harder to clear as the applicant pool grew more competitive.

16 math items, word problems and algebra mixed

0 of 16 answeredPick a letter: the reasoning for every choice opens under it.
Q1 of 16 · Arithmetic Reasoning (AR)

Twice a number, decreased by 7, equals 3 more than the number. What is the number?

  1. Translate as 2n − 7 = n + 3; subtracting n and adding 7 gives n = 10 (check: 20 − 7 = 13 = 10 + 3).
  2. −4 moves the 7 across without changing its sign (n = 3 − 7); adding 7 to both sides gives n = 10.
  3. 5 drops the n on the right side and solves 2n − 7 = 3.
  4. 4/3 writes "twice a number, decreased by 7" as 7 − 2n; 7 − 2n = n + 3 gives n = 4/3.
  5. −7 reads "3 more than the number" as 3n: 2n − 7 = 3n gives n = −7.

ID 1821338Report a problem

Q2 of 16 · Arithmetic Reasoning (AR)

A unit of 198 people has officers and enlisted members in a ratio of 2 to 9. How many officers are in the unit?

  1. 162 is 9 × 18, the number of enlisted members, not the number of officers.
  2. 18 is one part of the ratio (198 ÷ 11); the officers make up 2 parts, so they number 36.
  3. 44 is 2 × (198 ÷ 9): it uses 9 parts for the whole unit, but 2 + 9 = 11 parts make up the 198 people.
  4. The ratio 2 to 9 has 11 parts, so one part is 198 ÷ 11 = 18 people and the officers are 2 × 18 = 36.
  5. 22 divides 198 by 9, as if the enlisted share were the whole unit, and stops there.

ID 1821351Report a problem

Q3 of 16 · Arithmetic Reasoning (AR)

Adult tickets cost $12 and child tickets cost $7. A group of 9 people paid $88 in all. How many children were in the group?

  1. 2 divides the extra $25 above an all-child price ($88 − $63) by $12; that extra must be divided by the $5 price difference.
  2. 3 rounds $20 ÷ $7: it divides the $20 savings by the child price instead of by the $5 difference between the prices.
  3. Nine adults would cost $108; each child saves $5, and the group saved $20, so there were 20 ÷ 5 = 4 children (5 × $12 + 4 × $7 = $88).
  4. 7 is how many $12 tickets fit into $88 (88 ÷ 12 ≈ 7.3); that ignores that the group has 9 people of two kinds.
  5. 5 is the number of adults in the group; the question asks for children.

ID 1821383Report a problem

Q4 of 16 · Arithmetic Reasoning (AR)

Crates are shared among three squadrons in the ratio 2:3:4. The largest share is 72 crates more than the smallest share. How many crates are there in all?

  1. 288 is 72 × 4, the 72-crate gap multiplied by the largest ratio term.
  2. The largest and smallest shares differ by 4 − 2 = 2 parts, so one part is 72 ÷ 2 = 36 crates and all 9 parts are 324.
  3. 216 multiplies 72 by the 3 squadrons; the 72 crates are a difference of 2 parts, not one squadron's share.
  4. 162 treats the 72-crate gap as 4 parts (one part = 18); the gap between 4 parts and 2 parts is only 2 parts.
  5. 144 is the largest share alone (4 parts × 36), not the total of all three shares.

ID 1821392Report a problem

Q5 of 16 · Math Knowledge (MK)

A supply officer is cataloging equipment costs. A radio (R) costs $50 more than twice the cost of a headset (H). A battery (B) costs one-third as much as a headset. Which equation gives the cost of a radio in terms of the cost of a battery?

  1. R = 5B + 50 adds the factors 2 and 3 instead of multiplying them.
  2. From B = H/3, a headset costs H = 3B; substituting into R = 2H + 50 gives R = 2(3B) + 50, so R = 6B + 50.
  3. R = 6B + 150 multiplies the $50 by 3 as well; only H is replaced by 3B.
  4. R = (2/3)B + 50 reads the battery relation backward, as H = B/3.
  5. R = 2B + 50 puts B in place of H without converting; a headset costs three batteries.

ID 1858829Report a problem

Q6 of 16 · Arithmetic Reasoning (AR)

Two aircraft leave the same airfield at noon and fly in opposite directions, one at 45 knots and the other at 75 knots. At what time are they 360 nautical miles apart?

  1. 8:00 p.m. uses only the slower aircraft (360 ÷ 45 = 8 hours).
  2. 12:00 midnight subtracts the speeds (360 ÷ 30 = 12 hours), which fits two aircraft flying the same way, not opposite ways.
  3. 6:00 p.m. uses the average speed of 60 knots for a single aircraft; the distances of the two aircraft add, so the speeds add.
  4. Flying in opposite directions, the gap grows at 45 + 75 = 120 knots, so 360 ÷ 120 = 3 hours after noon, 3:00 p.m.
  5. 4:48 p.m. uses only the faster aircraft (360 ÷ 75 = 4.8 hours) and ignores the slower one moving away too.

ID 1941509Report a problem

Q7 of 16 · Arithmetic Reasoning (AR)

A club of 32 members collects $15 in dues from each member. It pays $180 to rent a hall and $6.50 per member for food. How much money is left?

  1. $272.00 subtracts the food but forgets the $180 hall rental.
  2. $300.00 subtracts the hall rental but forgets the $208 for food.
  3. $98.50 pays for food for 31 members instead of 32 (an off-by-one slip of $6.50).
  4. $293.50 subtracts $6.50 for food once instead of $6.50 for each of the 32 members.
  5. Dues bring in 32 × $15 = $480; the hall costs $180 and food 32 × $6.50 = $208, so $480 − $180 − $208 = $92.00 is left.

ID 1941520Report a problem

Q8 of 16 · Math Knowledge (MK)

A 10 by 8 by 6 block has a 2 by 2 square hole cut straight through its 10-unit length. What volume remains?

  1. The block is 10 × 8 × 6 = 480, and the hole is a 2 × 2 × 10 prism of 40, so 480 − 40 = 440 remains.
  2. 480 is the volume of the solid block; the hole has not been taken out.
  3. 448 subtracts a hole 8 units long (2 × 2 × 8 = 32); the hole runs through the 10-unit length.
  4. 456 subtracts a hole 6 units long (2 × 2 × 6 = 24) instead of 10 units long.
  5. 470 subtracts only 10, the hole's length, instead of its volume 2 × 2 × 10 = 40.

ID 2009966Report a problem

Q9 of 16 · Math Knowledge (MK)

If 2x/5 − 14 = 6, then x =

  1. 20 is the value of 2x/5 after adding 14; the last step, solving for x, is missing.
  2. 22 multiplies 2x/5 by 5 but not the 14: 2x − 14 = 30 gives x = 22. Every term has to be multiplied.
  3. −20 subtracts 14 from 6 instead of adding it (2x/5 = −8).
  4. 8 multiplies 20 by 2/5 instead of by its reciprocal 5/2.
  5. Add 14 to get 2x/5 = 20, then multiply by 5/2: x = 50 (check: 2 × 50 / 5 − 14 = 6).

ID 1821294Report a problem

Q10 of 16 · Math Knowledge (MK)

If x + y = 50 and 0.6x + 0.2y = 22, then x =

  1. 12 is the value of 0.4x; dividing by 0.4 is the missing last step.
  2. 15 writes 0.6x + 0.2(50 − x) as 0.6x + 0.2x + 10, adding the coefficients, so 0.8x = 12.
  3. Substitute y = 50 − x: 0.6x + 10 − 0.2x = 22, so 0.4x = 12 and x = 30 (then y = 20, and 18 + 4 = 22).
  4. 20 is the value of y, not x.
  5. 25 just splits 50 in half without using the second equation.

ID 1821298Report a problem

Q11 of 16 · Math Knowledge (MK)

What is the volume of a rectangular box 4 by 5 by 6?

  1. 148 is the surface area, 2 × (20 + 24 + 30), not the volume.
  2. 74 adds the three face areas once (20 + 24 + 30), half the surface area; it is not a volume.
  3. 30 is the area of one face, 5 × 6; the third dimension is missing.
  4. 15 adds the three dimensions (4 + 5 + 6) instead of multiplying them.
  5. Volume = length × width × height = 4 × 5 × 6 = 120.

ID 1821346Report a problem

Q12 of 16 · Math Knowledge (MK)

If 3u + v = 7 and u − v = 1, then

  1. u = 1, v = 4 satisfies 3u + v = 7 but gives u − v = −3, not 1.
  2. u = 3, v = 2 satisfies u − v = 1 but gives 3u + v = 11.
  3. u = 4, v = 3 satisfies only u − v = 1; 3u + v would be 15.
  4. Adding the equations removes v: 4u = 8, so u = 2, v = 1; the pair satisfies both (6 + 1 = 7, 2 − 1 = 1).
  5. u = 0, v = 7 satisfies only the first equation; u − v would be −7.

ID 1821413Report a problem

Q13 of 16 · Math Knowledge (MK)

For x, y > 0, √(72x5y8) equals

  1. 72 = 36 × 2, x5 = x4 · x and y8 = (y4)2; the square roots 6, x2, y4 come out and 2x stays inside: 6x2y4√(2x).
  2. 6x2y2√(2x) takes the fourth root of y8 instead of the square root; √(y8) = y4.
  3. 6x4y4√(2x) brings x4 out without halving its exponent; √(x4) = x2.
  4. 6x2y4√2 loses the leftover x: x5 = x4 · x, and that single x stays under the root.
  5. 36x2y4√(2x) brings 36 out without taking its square root; √36 = 6.

ID 1858819Report a problem

Q14 of 16 · Arithmetic Reasoning (AR)

A tool listed at $250 is sold for $195. What percent discount was given?

  1. The discount is $250 − $195 = $55, and 55 ÷ 250 = 0.22, a 22% discount off the list price.
  2. 28% divides the $55 discount by the $195 sale price; a discount is a share of the list price.
  3. 2.2% misplaces the decimal point when turning 0.22 into a percent.
  4. 78% is 195 ÷ 250, the share of the list price that was paid, not the discount.
  5. 55% copies the $55 dollar discount as if it were a percent.

ID 1940693Report a problem

Q15 of 16 · Math Knowledge (MK)

0.375 written as a fraction in lowest terms is

  1. 37/100 = 0.37 drops the last digit, 5 thousandths.
  2. 5/8 = 0.625 is the complement, 1 − 0.375, not 0.375 itself.
  3. 0.375 = 375/1000, and dividing both by 125 gives 3/8 (3 ÷ 8 = 0.375).
  4. 15/4 = 3.75 puts 375 over 100; three decimal places mean a denominator of 1,000.
  5. 3/80 = 0.0375, one place value too small.

ID 1940759Report a problem

Q16 of 16 · Math Knowledge (MK)

A cube has a surface area of 54. What is its volume?

  1. 54 is the surface area; volume and surface area of a cube are different quantities.
  2. Each of the 6 faces has area 54 ÷ 6 = 9, so an edge is 3 and the volume is 3³ = 27.
  3. 9 is the area of one face; the edge is √9 = 3 and the volume is 3³.
  4. 81 squares the face area 9 instead of cubing the edge 3.
  5. 729 cubes the face area 9 instead of the edge length 3.

ID 1941448Report a problem

Your tally shows here once every question above has an answer.

Where AFOQT math points slip away

  • The wrong base for a percent. A change is measured against the starting value. Write the base down before you divide.
  • Mixed units in one equation. A speed in miles per hour and a time in minutes give nonsense until one is converted. Convert first, then set up the equation.
  • The average of two rates. Out at one speed and back at another is not the midpoint of the two speeds, because you spend longer at the slower one. Use total distance over total time.
  • Answering a different question. Word problems often ask for the second quantity (the remainder, the other group, the later time). Reread the last line before you mark an option.
  • Signs and exponents. A negative exponent makes a reciprocal, not a negative number; the square root of a square is an absolute value.
  • Unchecked algebra. Plug a solution back into the original equation; the check takes seconds and catches most slips.

Full topic review lives on the ASVAB pages

The arithmetic, algebra and geometry behind both subtests are the same skills the ASVAB tests, and this site reviews them once: word problems on Arithmetic Reasoning, algebra and geometry on Math Knowledge. Those pages carry different questions from this one. What changes on the AFOQT is the format above: a fixed, timed block, no calculator and a composite role that makes Math Knowledge the most valuable subtest for rated applicants (composite matrix).

AFOQT math sets on your phone

Practice on your phone

AFOQT questions with the reasoning for every choice, in a study app (see both stores).

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The other AFOQT subtest pages

AFOQT math, briefly

Is AFOQT math harder than ASVAB math?

The topics overlap heavily: arithmetic word problems, algebra and basic geometry. The AFOQT feels harder because it is a fixed, timed block taken alongside officer applicants, and your percentile is set against other officer applicants, not against the national youth sample the ASVAB is normed on.

Which AFOQT composites use the math subtests?

Quantitative and Academic Aptitude use both. Math Knowledge also counts toward Pilot, CSO and ABM, so it matters for every rated job.

Can a pilot applicant skip Arithmetic Reasoning?

No. It is out of the Pilot composite, but it is half of Quantitative, and every applicant has to clear the Quantitative floor to commission.